Développper et réduire : A = -6 x(5x-3) B=(2x+3)(4-1) C=6a+9-(a-1)(5a+7) D=(x+8)(y-6)-(x+3)(2y+1)
Mathématiques
tiitine
Question
Développper et réduire :
A = -6 x(5x-3)
B=(2x+3)(4-1)
C=6a+9-(a-1)(5a+7)
D=(x+8)(y-6)-(x+3)(2y+1)
A = -6 x(5x-3)
B=(2x+3)(4-1)
C=6a+9-(a-1)(5a+7)
D=(x+8)(y-6)-(x+3)(2y+1)
1 Réponse
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1. Réponse nonotata
A = -6 x(5x-3)
= -30x +18
B=(2x+3)(4-1)
= 8x-2x+12-3
= 6x+9
C=6a+9-(a-1)(5a+7)
c= 6a+9 -(5a²+7a-5a-7)
c =6a+9 -5a²-2a+7
c= -5a²+4a+16
D=(x+8)(y-6)-(x+3)(2y+1)
= xy+6x+8y-48 -(2xy+x+6y+3)
= xy +14y-48 -2xy -x-6y-3
= -xy +8y -x -51