Help Identité remarquable et factorisation dévelloper svp C=(x+1)²+2(x-1)+1 H=(x-1)²-(1-x)(3+4x) J= (4x+8)(x-5)-3(x+2)(3x+1) Help Me Please/ Aidez mon SVP

Bonjour,

Developper :

C=(x+1)²+2(x+ 1)=>il y a une erreur j’ai modifié
C = x^2 + 2x + 1 + 2x + 2
C = x^2 + 4x + 3

H=(x-1)²-(1-x)(3+4x)
H = x^2 - 2x + 1 - (3 + 4x - 3x - 4x^2)
H = x^2 + 4x^2 - 2x - x + 1 - 3
H = 5x^2 - 3x - 2

J= (4x+8)(x-5)-3(x+2)(3x+1)
J = 4x^2 - 20x + 8x - 40 - 3(3x^2 + x + 6x + 2)
J = 4x^2 - 9x^2 - 12x - 21x - 40 - 6
J = -5x^2 - 33x - 46

Factoriser :

C=(x+1)²+2(x+1)
C = (x + 1)(x + 1 + 2)
C = (x + 1)(x + 3)

H=(x-1)²-(1-x)(3+4x)
H = (x - 1)^2 + (-1 + x)(3 + 4x)
H = (x - 1)(x - 1 + 3 + 4x)
H = (x - 1)(5x + 2)

J= (4x+8)(x-5)-3(x+2)(3x+1)
J = 4(x + 2)(x - 5) - 3(x + 2)(3x + 1)
J = (x + 2)[4(x - 5) - 3(3x + 1)]
J = (x + 2)(4x - 20 - 9x - 3)
J = (x + 2)(-5x - 23)

Bonsoir

♧ Développer :

C = (x+1)² + 2(x-1) + 1
C = x² + 2x + 1 + 2x - 2 - 1
C = x² + 4x - 2

H = (x-1)² - (1-x)(3+4x)
H = x² - 2x + 1 - (-4x² + x + 3)
H = x² - 2x + 1 + 4x² - x - 3
H = 5x² - 3x - 2

J = (4x+8)(x-5) - 3(x+2)(3x+1)
J = 4x² - 12x - 40 - 3(3x² + 7x + 2)
J = 4x² - 12x - 40 - 9x² - 21x - 6
J = - 5x² - 33x - 46

♧ Factoriser :

C = (x+1)² + 2(x-1) + 1
C = x (x+4)

H = (x-1)² - (1-x)(3+4x)
H = (x-1)(5x+2)

J = (4x+8)(x-5) - 3(x+2)(3x+1)
J = -(x+2)(5x+23)

Voilà ^^